x^2-8x+3=180

Solution for x^2-8x+3=180 equation:

x^2-8x+3=180

We move all terms to the left:

x^2-8x+3-(180)=0

We add all the numbers together, and all the variables

x^2-8x-177=0

a = 1; b = -8; c = -177;
Δ = b2-4ac
Δ = -82-4·1·(-177)
Δ = 772
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{772}=\sqrt{4*193}=\sqrt{4}*\sqrt{193}=2\sqrt{193}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{193}}{2*1}=\frac{8-2\sqrt{193}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{193}}{2*1}=\frac{8+2\sqrt{193}}{2}
$